∣z−2∣≤4⇒(x−2)2+y2≤16
∣z−2∣+∣z+2∣=5⇒a2x2+b2y2=1
⇒254x2+94y2=1

Maximum value of ∣z1−z2∣=6+25=217
JEE Main 2026 — Mathematics Algebra
Let A={z∈C:∣z−2∣⩽4} and B={z∈C:∣z−2∣+∣z+2∣=5}. Then the max {∣z1−z2∣:z1∈ A and z2∈ B} is :
Held on 28 Jan 2026 · Verified 6 Jul 2026.
217
8
9
215
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