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Let O be the origin, the point A be z_1=√3+2 √2 i, the point B (z_2 ) be such that √3 |z_2 |= |z_1 | and arg (z_2 )=arg (z_1 )+ π 6. Then

JEE Main 2025 — Mathematics Algebra

2025mcqhard

Let OOO be the origin, the point AAA be z1=3+22iz_1=\sqrt{3}+2 \sqrt{2} iz1​=3​+22​i, the point B(z2)B\left(z_2\right)B(z2​) be such that 3∣z2∣=∣z1∣\sqrt{3}\left|z_2\right|=\left|z_1\right|3​∣z2​∣=∣z1​∣ and arg⁡(z2)=arg⁡(z1)+π6\arg \left(z_2\right)=\arg \left(z_1\right)+\frac{\pi}{6}arg(z2​)=arg(z1​)+6π​. Then

Official previous-year question

Held on 28 Jan 2025 · Verified 6 Jul 2026.

Options

  1. A

    area of triangle ABO is 113\frac{11}{\sqrt{3}}3​11​

  2. B

    ABO is an obtuse angled isosceles triangle

  3. C

    area of triangle ABO is 114\frac{11}{4}411​

  4. D

    ABO is a scalene triangle

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