Given function is
f(x)=loge(5+4x2x−3)+sin−1(2−x4+3x)
For domain, the conditions are
5+4x2x−3>0 and 2−x4+3x≤1
Now, 5+4x2x−3>0⇒x∈(−∞,−45)∪[23,∞)
and −1≤2−x4+3x≤1
⇒(−1≤2−x4+3x)∩(2−x4+3x≤1)
⇒(2−x6+2x≥0)∩(2−x2+4x≤0)
⇒2−x6+2x⋅2−x2+4x≤0⇒x∈[−3,−21]
Hence, we get the domain of f as x∈[−3,−45) This means that α=−3,β=−45 Thus, α2+4β=9−5=4