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Let α, β be the distinct roots of the equation x^2- (t^2-5 t+6 ) x+1=0, t ∈ mathbbR and a_n=α^n+β^n. Then the minimum value of a_2023+a_2025 a_2024 is

JEE Main 2024 — Mathematics Algebra

2024mcqmedium

Let α,β\alpha, \betaα,β be the distinct roots of the equation x2−(t2−5t+6)x+1=0,t∈Rx^2-\left(t^2-5 t+6\right) x+1=0, t \in \mathbb{R}x2−(t2−5t+6)x+1=0,t∈R and an=αn+βna_n=\alpha^n+\beta^nan​=αn+βn. Then the minimum value of a2023+a2025a2024\frac{a_{2023}+a_{2025}}{a_{2024}}a2024​a2023​+a2025​​ is

Official previous-year question

Held on 6 Apr 2024 · Verified 6 Jul 2026.

Options

  1. A

    −1/4-1 / 4−1/4

  2. B

    −1/4-1 / 4−1/4

  3. C

    −1/2-1 / 2−1/2

  4. D

    1/41 / 41/4

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