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Let the system of linear equations x+y+kz=2 2x+3y-z=1 3x+4y+2z=k have infinitely many solutions. Then the system (k+1)x+(2k-1)y=7 (2k+1)x+|k+5|y=10…

JEE Main 2023 — Mathematics Algebra

2023mcqmedium

Let the system of linear equations

x+y+kz=2x+y+kz=2x+y+kz=2

2x+3y−z=12x+3y-z=12x+3y−z=1

3x+4y+2z=k3x+4y+2z=k3x+4y+2z=k

have infinitely many solutions. Then the system

(k+1)x+(2k−1)y=7(k+1)x+(2k-1)y=7(k+1)x+(2k−1)y=7

(2k+1)x+∣k+5∣y=10(2k+1)x+|k+5|y=10(2k+1)x+∣k+5∣y=10 has :

Official previous-year question

Held on 30 Jan 2023 · Verified 6 Jul 2026.

Options

  1. A

    infinitely many solutions

  2. B

    unique solution satisfying x−y=1x-y=1x−y=1

  3. C

    no solution

  4. D

    unique solution satisfying x+y=1x+y=1x+y=1

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