Given,
First term of A.P are 1,2,3....10, so general term of the first term will be i
And common difference are 1,3,5,...., so general term of common difference is given by 2i−1
Now sum of the A.P is given by,
Si=212[2×i+(12−1)(2i−1)]
⇒Si=6[2×i+11(2i−1)]
⇒Si=144i−66
So, i=1∑10Si=i=1∑10144i−66i=1∑101
⇒i=1∑10Si=144(210×11)−66×10
⇒i=1∑10Si=792(10)−66×10
⇒i=1∑10Si=7260
Hence this is the correct option.