Given that (a+bx+cx2)10=i=10∑20pixi,a,b,c∈N
General term : r1!r2!r3!10!(a)r1(bx)r2(cx2)r3
For coefficient. of x:r2+2r3=1
Let r19r21r30
∴ coefficient of x=9!10!a9b1=20
⇒a9⋅b=2......(i)
Coefficient of ⇒x2:8!2!0!10!a8⋅b2+9!0!1!10!⋅a9⋅c=210
⇒45a8⋅b2+10⋅a9⋅c=210
⇒9a8b2+2a9⋅c=42.......(ii)
As a,b,c∈N, so by hit and trial in equation (i)&(\mathrm{ii}) we get, a=1,b=2,c=3
Hence, 2(a+b+c)=2(3+2+1)=12