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Let A=[ … ] and B=[ … ], where i=√-1. If M=A^T BA, then the inverse of the matrix AM^2023 A^T is

JEE Main 2023 — Mathematics Algebra

2023mcqmedium

Let A=[110310−310110]A=[\begin{matrix}\frac{1}{\sqrt{10}} & \frac{3}{\sqrt{10}} \\ \frac{-3}{\sqrt{10}} & \frac{1}{\sqrt{10}}\end{matrix}]A=[10​1​10​−3​​10​3​10​1​​] and B=[1−i01]B=[\begin{matrix}1 & -i \\ 0 & 1\end{matrix}]B=[10​−i1​], where i=−1i=\sqrt{-1}i=−1​. If M=ATBAM={A}^{T}\mathrm{BA}M=ATBA, then the inverse of the matrix AM2023AT{\mathrm{AM}}^{2023}{A}^{T}AM2023AT is

Official previous-year question

Held on 25 Jan 2023 · Verified 6 Jul 2026.

Options

  1. A

    [1−2023i01][\begin{matrix}1 & -2023i \\ 0 & 1\end{matrix}][10​−2023i1​]

  2. B

    [10−2023i1][\begin{matrix}1 & 0 \\ -2023i & 1\end{matrix}][1−2023i​01​]

  3. C

    [102023i1][\begin{matrix}1 & 0 \\ 2023i & 1\end{matrix}][12023i​01​]

  4. D

    [12023i01][\begin{matrix}1 & 2023i \\ 0 & 1\end{matrix}][10​2023i1​]

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