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The number of positive integers k such that the constant term in the binomial expansion of (2x^3+ 3 x^k)^12,x≠ 0 is 2^8· l, where l is an odd…

JEE Main 2022 — Mathematics Algebra

2022integermedium

The number of positive integers kkk such that the constant term in the binomial expansion of (2x3+3xk)12,x≠0{(2{x}^{3}+\frac{3}{{x}^{k}})}^{12},x\neq 0(2x3+xk3​)12,x=0 is 28⋅l{2}^{8}\cdot l28⋅l, where lll is an odd integer, is ______.

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Held on 28 Jun 2022 · Verified 6 Jul 2026.

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