Skip to main content

If the minimum value of f(x)= 5x^2 2+ α x^5,x>0, is 14, then the value of α is equal to

JEE Main 2022 — Mathematics Algebra

2022mcqeasy

If the minimum value of f(x)=5x22+αx5,x>0f(x)=\frac{5{x}^{2}}{2}+\frac{\alpha }{{x}^{5}},x>0f(x)=25x2​+x5α​,x>0, is 141414, then the value of α\alphaα is equal to

Official previous-year question

Held on 28 Jul 2022 · Verified 6 Jul 2026.

Options

  1. A

    323232

  2. B

    646464

  3. C

    128128128

  4. D

    256256256

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

JEE Main Algebra in other years

More JEE Main Algebra questions

Other Mathematics topics for JEE Main

Keep practicing Algebra

Work through every JEE Main Algebra PYQ, year by year.

Browse all Mathematics topics