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If the maximum value of the term independent of t in the expansion of (t^2 x^ 1 5+ (1-x)^^ 1 10 t)^15,x≥ 0, is K, then 8K is equal to .

JEE Main 2022 — Mathematics Algebra

2022integereasy

If the maximum value of the term independent of ttt in the expansion of (t2x15+(1−x)110t)15,x≥0{({t}^{2}{x}^{\frac{1}{5}}+\frac{{(1-x)}^{{}^{\frac{1}{10}}}}{t})}^{15},x\geq 0(t2x51​+t(1−x)101​​)15,x≥0, is KKK, then 8K8K8K is equal to _____ .

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Held on 25 Jul 2022 · Verified 6 Jul 2026.

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