If r1 and r2 are roots of the quadratic ax2+bx+c=0
then r1n=31r1n−2−228r1n−1 and r2n=31r2n−2−228r2n−1
So, r1n−r2n=31(r1n−2−r2n−2)−228(r1n−1−r2n−1)
Or an−31an−1+228an−2=0 where an=r1n−r2n
Since 19&12 are the roots of the quadratic x2−31x+228=0
we know, an−31an−1+228an−2=0
Now, for n=10,α10−31α3+228α8=0
⇒57α831α9−α10=4