f(x)=ax,a>0
f(x)=2ax+a−x+ax−a−x
⇒f1(x)=2ax+a−x
f2(x)=2ax−a−x
⇒f1(x+y)+f1(x−y)
=2ax+y+a−x−y+2ax−y+a−x+y
=2(ax+a−x)(ay+a−y)
=f1(x)×2f1(y)
=2f1(x)f1(y)
JEE Main 2019 — Mathematics Algebra
Let f(x)=ax(a>0) be written as f(x)=f1(x)+f2(x), where f1(x) is an even function and f2(x) is an odd function. Then f1(x+y)+f1(x−y) equals:
Held on 8 Apr 2019 · Verified 6 Jul 2026.
2f1(x)f1(y)
2f1(x+y)f1(x−y)
2f1(x)f2(y)
2f1(x+y)f2(x−y)
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