f(x)=1+x2x,x∈R Let, y=1+x2x ⇒yx2−x+y=0⇒x=21±1−4y2 ⇒1−4y2≥0 ⇒1≥4y2 ⇒∣y∣≤21 ⇒−21≤y≤21 ⇒ The range of f is [−21,21].
Let f: R → R be defined by f(x)= x 1+x^2, x ∈ R . Then the range of f is
JEE Main 2019 — Mathematics Algebra
Let f:R→R be defined by f(x)=1+x2x,x∈R. Then the range of f is
Held on 11 Jan 2019 · Verified 6 Jul 2026.
Options
- A
[−21,21]
- B
R−[−1,1]
- C
R−[−21,21]
- D
(−1,1)−{0}
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