Let a1=a,a2=ar,a3=ar2…a10=ar9 where r= common ratio of given G.P. Given, a1a3=25 ⇒aar2=25 ⇒r=±5 Now, a5a9=ar4ar8=r4=(±5)4=54
Let a_1, a_2, …, a_10 be a G.P. If a_3 a_1=25, then a_9 a_5 equals :
JEE Main 2019 — Mathematics Algebra
Let a1,a2,…,a10 be a G.P. If a1a3=25, then a5a9 equals :
Held on 11 Jan 2019 · Verified 6 Jul 2026.
Options
- A
54
- B
4(52)
- C
53
- D
2(52)
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