Given series, 12+2⋅22+32+2⋅42+52+2⋅62+…
Here, A=12+2⋅22+32+2⋅42+...20 terms
=(12+22+32+42+...20terms)+(22+42+62+...10terms)
=620⋅21⋅41+4(610⋅11⋅21)
⇒A=4410
Similarly for B=(12+22+33+...40terms)+(22+42+62+...20terms)
⇒B=640×41×81+64×20×21×41
⇒B=33620
Now, B−2A=24800=100λ (Given)
⇒λ=248