Since, (b,c)∈R1 but (c,b)∈/R1
Hence, R1 is not symmetric.
In R1:(b,c)∈R1 and (c,a)∈R1 but (b,a)∈/R1
So, R1 is not transitive.
R2 is symmetric.
In R2:(b,a)∈R2 and (a,c)∈R1 but (b,c)∈/R2
So, R2 is not transitive.
JEE Main 2018 — Mathematics Algebra
Consider the following two binary relations on the set A=a,b,c:R1=(c,a),(b,b),(a,c),(c,c),(b,c),(a,a) and R2=(a,b),(b,a),(c,c),(c,a),(a,a),(b,b),(a,c), then :
Held on 15 Apr 2018 · Verified 6 Jul 2026.
R2 is symmetric but it is not transitive
both R1 and R2 are not symmetric
both R1 and R2 are transitive
R1 is not symmetric but it is transitive
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