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Let A=x_1,x_2,… ,x_7 and B=y_1,y_2,y_3 be two sets containing seven and three distinct elements respectively. Then the total number of functions f:A→…

JEE Main 2015 — Mathematics Algebra

2015mcqhard

Let A=x1,x2,…,x7andB=y1,y2,y3A={{x}_{1},{x}_{2},\ldots ,{x}_{7}} \text{and} B={{y}_{1},{y}_{2},{y}_{3}}A=x1​,x2​,…,x7​andB=y1​,y2​,y3​ be two sets containing seven and three distinct elements respectively. Then the total number of functions f:A→Bf:A\rightarrow Bf:A→B that are onto, if there exist exactly three elements xxx in AAA such that f(x)=y2,f(x)={y}_{2},f(x)=y2​, is equal to:

Official previous-year question

Held on 11 Apr 2015 · Verified 6 Jul 2026.

Options

  1. A

    12⋅7C212{\cdot }^{7}{C}_{2}12⋅7C2​

  2. B

    16⋅7C316{\cdot }^{7}{C}_{3}16⋅7C3​

  3. C

    14⋅7C314\cdot { }^{7}{C}_{3}14⋅7C3​

  4. D

    14⋅7C214{\cdot }^{7}{C}_{2}14⋅7C2​

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