Y⊆X,Z⊆X Let a∈X, then we have following chances that (1) a∈Y,a∈Z (2) a∈/Y,a∈Z (3) a∈Y,a∈/Z (4) a∈/Y,a∈/Z We require Y∩Z=ϕ Hence (2), (3), (4) are chances for 'a' to satisfy Y∩Z=ϕ. ∴Y∩Z=ϕ has 3 chances for a. Hence for five elements of X, the number of required chances is 3×3×3×3×3=35
Let X=1,2,3,4,5. The number of different ordered pairs (Y, Z) that can be formed such that Y subseteq X, Z subseteq X and Y ∩ Z is empty, is
JEE Main 2012 — Mathematics Algebra
Let X={1,2,3,4,5}. The number of different ordered pairs (Y,Z) that can be formed such that Y⊆X,Z ⊆X and Y∩Z is empty, is
Held on 30 Apr 2012 · Verified 6 Jul 2026.
Options
- A
52
- B
35
- C
25
- D
53
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