n=mC2=2m(m−1) Since m and (m−1) are two consecutive natural numbers, therefore their product is an even natural number. So 2m(m−1) is also a natural number. Now 2m(m−1)=2m2−m ∴2m(m−1)C2=2(2m2−m)(2m2−m−1)=8m(m−1)(m2−m−2)=8m(m−1)[m2−2m+m−2]=8m(m−1)[m(m−2)+1(m−2)]=8m(m−1)(m−2)(m+1) 
If n= ^m C_2, then the value of ^n C_2 is given by
JEE Main 2012 — Mathematics Algebra
If n=mC2, then the value of nC2 is given by
Held on 19 May 2012 · Verified 6 Jul 2026.
Options
- A
3(m+1C4)
- B
m−1C4
- C
m+1C4
- D
2(m+2C4)
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