(x−1)3+8=0⇒(x−1)=(−2)(1)1/3 ⇒x−1=−2 or −2ω or −2ω2 or n=−1 or 1−2ω or 1−2ω2.
If the cube roots of unity are 1, ω, ω^2 then the roots of the equation (x-1)^3+8=0, are
JEE Main 2005 — Mathematics Algebra
If the cube roots of unity are 1,ω,ω2 then the roots of the equation (x−1)3+8=0, are
Held on 30 Apr 2005 · Verified 6 Jul 2026.
Options
- A
−1,−1+2ω,−1−2ω2
- B
−1,−1,−1
- C
−1,1−2ω,1−2ω2
- D
−1,1+2ω,1+2ω2
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