JEE Main Chemistry — Organic Chemistry previous year questions with solutions.
Match the LIST-I with LIST-II $\begin{array}{|l|l|l|l|} \hline & \begin{array}{l} \text{LIST-I} \\ \text{(Reagent)} \end{array} & & \begin{array}{c} \text{LIST-II} \\ \text{(Functional Group} \\ \text{detected)} \end{array} \\ \hline \text{A.} & \begin{array}{l} \text{Sodium} \\ \text{bicarbonate} \\ \text{solution} \end{array} & \text{I.} & \begin{array}{l} \text{double} \\ \text{bond/unsaturation} \end{array} \\ \hline \text{B.} & \begin{array}{l} \text{Neutral ferric} \\ \text{chloride} \end{array} & \text{II.} & \text{carboxylic acid} \\ \hline \text{C.} & \begin{array}{l} \text{ceric} \\ \text{ammonium} \\ \text{nitrate} \end{array} & \text{III.} & \text{phenolic - OH} \\ \hline \text{D.} & \begin{array}{l} \text{alkaline} \\ \text{KMnO} \end{array} & \text{IV.} & \text{alcoholic - OH} \\ \hline \end{array}$ Choose the correct answer from the options given below :
Match the LIST-I with LIST-II $\begin{array}{|l|l|l|l|}\hline & \text{LIST-I} & & \text{LIST-II} \\ \hline \text{A.} & \text{Carbocation} & \text{I.} & \begin{array}{l} \text{Species that can} \\ \text{supply a pair of} \\ \text{electrons.} \end{array} \\ \hline \text{B.} & \begin{array}{l} \text{C-Free} \\ \text{radical} \end{array} & \text{II.} & \begin{array}{l} \text{Species that can} \\ \text{receive a pair of} \\ \text{electrons.} \end{array} \\ \hline \text{C.} & \text{Nucleophile} & \text{III.} & \begin{array}{l} sp ^2 \text{ hybridized} \\ \text{carbon with empty} \\ \text{p-orbital.} \end{array} \\ \hline \text{D.} & \text{Electrophile} & \text{IV.} & \begin{array}{l} sp ^2 / sp ^3 \text{ hybridized} \\ \text{carbon with one} \\ \text{unpaired electron.} \end{array} \\ \hline \end{array}$ Choose the correct answer from the options given below :
Match the Compounds (List - I) with the appropriate Catalyst/Reagents (List - II) for their reduction into corresponding amines.  Choose the correct answer from the options given below :
Match List-I with List-II  Choose the correct answer from the options given below :
Match List-I with List-II  Choose the correct answer from the options given below :
Match List-I with List-II  Choose the correct answer from the options given below :
Match List-I with List-II - $\begin{array}{|l|l|l|l|}<br />\hline & \begin{array}{l}<br />\text { List-I } \\ \text { (Separation of) }<br />\end{array} & & \begin{array}{l}<br />\text { List-II } \\ \text { (Separation } \\ \text { Technique) }<br />\end{array} \\ \hline \text { (A) } & \begin{array}{l}<br />\text { Aniline from } \\ \text { aniline-water } \\ \text { mixture }<br />\end{array} & \text { (I) } & \begin{array}{l}<br />\text { Simple } \\ \text { distillation }<br />\end{array} \\ \hline \text { (B) } & \begin{array}{l}<br />\text { Glycerol from } \\ \text { spent-lye in soap } \\ \text { industry }<br />\end{array} & \text { (II) } & \begin{array}{l}<br />\text { Fractional } \\ \text { distillation }<br />\end{array} \\ \hline \text { (C) } & \begin{array}{l}<br />\text { Different } \\ \text { fractions of crude } \\ \text { oil in petroleum } \\ \text { industry }<br />\end{array} & \text { (III) } & \begin{array}{l}<br />\text { Distillation } \\ \text { at reduced } \\ \text { pressure }<br />\end{array} \\ \hline \text { (D) } & \begin{array}{l}<br />\text { Chloroform- } \\ \text { Aniline mixture }<br />\end{array} & \text { (IV) } & \begin{array}{l}<br />\text { Steam } \\ \text { distillation }<br />\end{array} \\ \hline<br />\end{array}$ Choose the correct answer from the options given below :
Match List - I with List - II. \(\begin{array}{ll|ll} & \begin{array}{l} \text { List - I } \\ \text { (Carbohydrate) } \end{array} & \begin{array}{l} \text { List - II } \\ \text { (Linkage Source) } \end{array} \\ \hline \text { (A) } & \text { Amylose } & \text { (I) } \beta-C_1-C_4 \text {, plant } \\ \text { (B) } & \text { Cellulose } & \text { (II) } \alpha-C_1-C_4, \text { animal } \\ \text { (C) } & \text { Glycogen } & \text { (III) } \alpha-C_1-C_4, \alpha-C_1-C_6, \text { plant } \\ \text { (D) } & \text{ Amylopectin } & \text { (IV) } \alpha-C_1-C_4, \text { plant } \end{array}\) Choose the correct answer from the options given below :
Match List - I with List - II.  Choose the correct answer from the options given below :
Match List - I with List - II.  Choose the correct answer from the options given below :
 The maximum number of RBr producing 2-methylbutane by above sequence of reactions is ________ - (Consider the structural isomers only)
 Choose the correct answer from the options given below :
 Choose the correct option for structures of A and $B$, respectively.
 Choose the correct answer from the options given below :
 Choose the correct answer from the options given below :
 Residue $(\mathrm{A})+\mathrm{HCl}$ (dil) $\rightarrow$ Compound $(\mathrm{B})$ Structure of residue (A) and compound (B) formed respectively is :
 0.1 mole of compound ' S ' will weigh _______ g. (Given molar mass in \(\mathrm{g} \mathrm{mol}^{-1} \mathrm{C}: 12, \mathrm{H}: 1, \mathrm{O}: 16\))
The molecular formula of benzene is:
Isomeric hydrocarbons $\quad \rightarrow \quad$ negative Baeyer's test (Molecular formula $\mathrm{C}_9 \mathrm{H}_{12}$ ) The total number of isomers from above with four different non-aliphatic substitution sites is -