Points are collinear if 2−1a143111=0.
Expand: 2(4−3)−1(−1−a)+1(−3−4a)=0.
2+1+a−3−4a=0⇒−3a=0⇒a=0.
CUET UG 2023 — Mathematics Algebra
If the points (2, 1), (−1,4) and (a, 3) are collinear then the value/(s) of a is/(are) :
Held on 15 Jun 2023 · Verified 13 Jul 2026.
1, 2
3, 0
0
2, 1
Sign in to track your attempts and accuracy.
Sign in to keep a private note on this question. Nothing you write is ever public.
If f(x) = 2x + 3, then f⁻¹(x) is:
If $\vec{a}$ is a unit vector perpendicular to both the vectors $\vec{b} = \hat{j} + \hat{2k}$ and $\vec{c} = \hat{i} + 2\hat{j}$, then $\hat{a}$ is equal to
If the roots of the equation x² - 5x + k = 0 are in the ratio 2:3, then the value of k is:
A function $f: \mathbb{R} \rightarrow \{x \in \mathbb{R}: -1 < x < 1\}$ is defined as $f(x) = \frac{x}{1+|x|}$, then $f$ is:
If A is a square matrix such that $A^2 = A$ and I is the identity matrix of same order as A, then the value of $(A-2I)^2 - (2A + I)^2 + 11A$ is:
Work through every CUET UG Algebra PYQ, year by year.