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A function f: mathbbR → x ∈ mathbbR: -1 < x < 1 is defined as f(x) = x 1+|x|, then f is:

CUET UG 2025 — Mathematics Algebra

2025mcqmedium

A function f:R→{x∈R:−1<x<1}f: \mathbb{R} \rightarrow \{x \in \mathbb{R}: -1 < x < 1\}f:R→{x∈R:−1<x<1} is defined as f(x)=x1+∣x∣f(x) = \frac{x}{1+|x|}f(x)=1+∣x∣x​, then fff is:

Official previous-year question

Held on 19 May 2025 · Verified 13 Jul 2026.

Options

  1. A

    neither one-one nor onto

  2. B

    one-one only

  3. C

    onto only

  4. D

    both one-one and onto

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