Order of P=2×m, Q=k×n, R=m×2, S=2×3.
For PQ to be defined: m=k, giving order 2×n.
For RS to be defined: inner dim 2=2 ok, giving order m×3.
For PQ+RS, both must have same order: 2×n=m×3, so m=2 and n=3. Hence m=k=2, n=3.
Assume P, Q, R and S are matrices of order 2 × m, k × n, m × 2 and 2 × 3 respectively. The restrictions on k, m and n, so that PQ + RS is defined are
CUET UG 2022 — Mathematics Algebra
2022mcqmedium
Assume P, Q, R and S are matrices of order 2×m, k×n, m×2 and 2×3 respectively. The restrictions on k, m and n, so that PQ+RS is defined are
Official previous-year question
Held on 30 Aug 2022 · Verified 13 Jul 2026.
Options
- A
m=3,n=2
- B
m=n, k is arbitrary
- C
m=k, n is arbitrary
- D
m=k=2,n=3
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