Two successive frequencies of closed pipe
4lnv=220 ....(i)
4l(n+2)v=260 ......(ii)
Dividing (ii) by (i), we get
nn+2=220260=1113
11n+22=13n
n=11
So, 114lv=220
4lv=20
So fundamental frequency is 20 Hz.
NEET UG 2017 — Physics Waves & Oscillations
The two nearest harmonics of a tube closed at one end and open at other end are 220 Hz and 260 Hz. What is the fundamental frequency of the system?
Held on 30 Apr 2017 · Verified 9 Jul 2026.
10 Hz
20 Hz
30 Hz
40 Hz
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