For a particle executing SHM acceleration (a) ∝−ω2 displacement (x) Given x=asin2ωt Differentiating the above equation w.r.t, we get dtdx=2aω(sinωt)(cosωt) Again differentiating, we get dt2d2x=a=2aω2[cos2ωt−sin2ωt]=2aω2cos2ωt The given equation does not satisfy the condition for SHM [Eq. (i)] . Therefore, motion is not simple harmonic.