It is given that: y(x1t)=8.0sin(0.5πx−4πt−9λ) Compare this equation with standard equation y=asin(λ2πx− T2πt+ϕ) we have λ2π⇒λT2π⇒TU=T1=0.5π=0.5π2π=4 m=4π=21sec=y21=2H2.
NEET UG 2006 — Physics Waves & Oscillations
A transverse wave propagating along x-axis is represented by y(x,t)=8.0 sin(0.5πx−4πt−π/4) where x is in metres and t is in seconds. The speed of the wave is:
Held on 30 Apr 2006 · Verified 9 Jul 2026.
8 m/s
4πm/s
0.5πm/s
21 m/s
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