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A mass is suspended separately by two different springs in successive order, then the time period is T_1 and T_2, respectively. If it is connected by…

NEET UG 2002 — Physics Waves & Oscillations

2002mcqmedium

A mass is suspended separately by two different springs in successive order, then the time period is T1T_1T1​ and T2T_2T2​, respectively. If it is connected by both spring as shown in figure, then the time period T0T_0T0​, so the correct reaction is: NEET 2002 Physics, Oscillations — question figure

Official previous-year question

Held on 30 Apr 2002 · Verified 9 Jul 2026.

Options

  1. A

    T02=T12+T22T_0^2=T_1^2+T_2^2T02​=T12​+T22​

  2. B

    T0−2=T1−2+T2−2T_0^{-2}=T_1^{-2}+T_2^{-2}T0−2​=T1−2​+T2−2​

  3. C

    T0−1=T1−1+T2−1T_0^{-1}=\mathrm{T}_1^{-1}+\mathrm{T}_2^{-1}T0−1​=T1−1​+T2−1​

  4. D

    T0=T1+T2T_0=T_1+T_2T0​=T1​+T2​

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