Time period of spring T=2π Km ∴K=4π2T2m⇒K∝T21 For parallel combination of spring K=K1+K2 ∴T021=T121+T221⇒T0−2=T1−2+T2−2
A mass is suspended separately by two different springs in successive order, then the time period is T1 and T2, respectively. If it is connected by both spring as shown in figure, then the time period T0, so the correct reaction is: 
Held on 30 Apr 2002 · Verified 9 Jul 2026.
T02=T12+T22
T0−2=T1−2+T2−2
T0−1=T1−1+T2−1
T0=T1+T2
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