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Let the length of the latus rectum of an ellipse x^2 a^2+ y^2 b^2=1,(a>b), be 30. If its eccentricity is the maximum value of the function f(t)=- 3…

JEE Main 2026 — Mathematics Coordinate Geometry

2026mcqmedium

Let the length of the latus rectum of an ellipse x2a2+y2b2=1,(a>b)\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1,(a>b)a2x2​+b2y2​=1,(a>b), be 30. If its eccentricity is the maximum value of the function f(t)=−34+2t−t2f(t)=-\frac{3}{4}+2 t-t^{2}f(t)=−43​+2t−t2, then (a2+b2a^{2}+b^{2}a2+b2) is equal to

Official previous-year question

Held on 24 Jan 2026 · Verified 6 Jul 2026.

Options

  1. A

    276

  2. B

    256

  3. C

    516

  4. D

    496

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