f(t)=−t2+2t−43=−(t−1)2+41.
Maximum value =41, so e=41.
b2=a2(1−e2)=a2(1−161)=1615a2.
Latus rectum =a2b2=a2⋅15a2/16=815a=30⇒a=16.
b2=1615×256=240.
a2+b2=256+240=496.
JEE Main 2026 — Mathematics Coordinate Geometry
Let the length of the latus rectum of an ellipse a2x2+b2y2=1,(a>b), be 30. If its eccentricity is the maximum value of the function f(t)=−43+2t−t2, then (a2+b2) is equal to
Held on 24 Jan 2026 · Verified 6 Jul 2026.
276
256
516
496
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