Skip to main content

Let y^2=12 x be the parabola with its vertex at O. Let P be a point on the parabola and A be a point on the x-axis such that angle OPA=90°. Then the…

JEE Main 2026 — Mathematics Coordinate Geometry

2026mcqmedium

Let y2=12xy^{2}=12 xy2=12x be the parabola with its vertex at O. Let P be a point on the parabola and A be a point on the xxx-axis such that ∠OPA=90∘\angle \mathrm{OPA}=90^{\circ}∠OPA=90∘. Then the locus of the centroid of such triangles OPA is :

Official previous-year question

Held on 21 Jan 2026 · Verified 6 Jul 2026.

Options

  1. A

    y2−2x+8=0y^{2}-2 x+8=0y2−2x+8=0

  2. B

    y2−9x+6=0y^{2}-9 x+6=0y2−9x+6=0

  3. C

    y2−4x+8=0y^{2}-4 x+8=0y2−4x+8=0

  4. D

    y2−6x+4=0y^{2}-6 x+4=0y2−6x+4=0

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

JEE Main Coordinate Geometry in other years

More JEE Main Coordinate Geometry questions

Other Mathematics topics for JEE Main

Keep practicing Coordinate Geometry

Work through every JEE Main Coordinate Geometry PYQ, year by year.

Browse all Mathematics topics