Let a point A lie between the parallel lines L_1 and L_2 such that its distances from L_1 and L_2 are 6 and 3 units, respectively. Then the area (in…
JEE Main 2026 — Mathematics Coordinate Geometry
2026mcqmedium
Let a point A lie between the parallel lines L1 and L2 such that its distances from L1 and L2 are 6 and 3 units, respectively. Then the area (in sq. units) of the equilateral triangle ABC, where the points B and C lie on the lines L1 and L2, respectively, is :
Official previous-year question
Held on 21 Jan 2026 · Verified 6 Jul 2026.
Options
A
156
B
213
C
122
D
27
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Solution
Let L2:y=0, L1:y=9.
Point A at (0,3), B at (xB,9), C at (xC,0).
AB2=xB2+36, AC2=xC2+9, BC2=(xB−xC)2+81.
From AB=AC: xB2−xC2=−27.
From AB=BC: 2xBxC=xC2+45.
Solving: 3xC4−198xC2−2025=0.
Let u=xC2: u2−66u−675=0⇒u=75.
a2=xC2+9=84.
Area =43×84=213.
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