
Slope of the third side = slope of the perpendicular bisector of given lines h:5−x+2y−4=±2x+y−4 h1:2(−x+2y−4)=5(x+y−4)h2:2(−x+2y−4)=−5(x+y−4)ML1:−[5−225+2]ML2:−[5+225−2]ML1+ML2=−[5−225+2+5+225−2] =−[−3(5+2)(5+22)+(5−2)(5−22)]=6