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The length of the chord of the ellipse x^2 4+ y^2 2=1, whose mid-point is (1, 1 2 ), is :

JEE Main 2025 — Mathematics Coordinate Geometry

2025mcqmedium

The length of the chord of the ellipse x24+y22=1\frac{x^2}{4}+\frac{y^2}{2}=14x2​+2y2​=1, whose mid-point is (1,12)\left(1, \frac{1}{2}\right)(1,21​), is :

Official previous-year question

Held on 23 Jan 2025 · Verified 6 Jul 2026.

Options

  1. A

    5315\frac{5}{3} \sqrt{15}35​15​

  2. B

    1315\frac{1}{3} \sqrt{15}31​15​

  3. C

    2315\frac{2}{3} \sqrt{15}32​15​

  4. D

    15\sqrt{15}15​

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