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Let the shortest distance from ( a, 0), agt0, to the parabola y^2=4 x be 4 . Then the equation of the circle passing through the point (a, 0) and the…

JEE Main 2025 — Mathematics Coordinate Geometry

2025mcqmedium

Let the shortest distance from (a,0),a>0(\mathrm{a}, 0), \mathrm{a}\gt0(a,0),a>0, to the parabola y2=4xy^2=4 xy2=4x be 4 . Then the equation of the circle passing through the point (a,0)(a, 0)(a,0) and the focus of the parabola, and having its centre on the axis of the parabola is :

Official previous-year question

Held on 23 Jan 2025 · Verified 6 Jul 2026.

Options

  1. A

    x2+y2−10x+9=0x^2+y^2-10 x+9=0x2+y2−10x+9=0

  2. B

    x2+y2−6x+5=0x^2+y^2-6 x+5=0x2+y2−6x+5=0

  3. C

    x2+y2−4x+3=0x^2+y^2-4 x+3=0x2+y2−4x+3=0

  4. D

    x2+y2−8x+7=0x^2+y^2-8 x+7=0x2+y2−8x+7=0

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