Equation of parabola
(x+2)2+(y−1)2=(52x+y+2)2

5[(x+2)2+(y−1)2]=(2x+y+2)2
Put x=−2,5(y−1)2=(y−2)2
$\begin{aligned}
& 5\left(y^2-2 y+1\right)=y^2-4 y+4 \
& \Rightarrow 4 y^2-6 y+1=0 \Rightarrow y_1+y_2=\frac{3}{2}
\end{aligned}$
JEE Main 2025 — Mathematics Coordinate Geometry
Let P be the parabola, whose focus is (−2,1) and directrix is 2x+y+2=0. Then the sum of the ordinates of the points on P , whose abscissa is -2 , is
Held on 7 Apr 2025 · Verified 6 Jul 2026.
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