A : ∣x−1∣≤4 and ∣y−5∣≤6⇒−4≤x−1≤4⇒−6≤y−5≤6⇒−3≤x≤5⇒−1≤y≤11 B : 16(x−2)2+9(y−6)2≤144 B : 9(x−2)2+16(y−6)2≤1

From Diagram B⊂A
JEE Main 2025 — Mathematics Coordinate Geometry
Let
A={(α,β)∈R×R:∣α−1∣≤4 and ∣β−5∣≤6}
and
B={(α,β)∈R×R:16(α−2)2+9(β−6)2≤144}
Held on 7 Apr 2025 · Verified 6 Jul 2026.
B⊂A
A∪B={(x,y):−4≤x≤4,−1≤y≤11}
neither A⊂B nor B⊂A
A⊂B
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