Let the centre be (−2a,26a−2)≡(−2a,3a−1) Centre is equal distance from (4,2) and (0,2) ⇒(4+2a)2+(3a−3)2=(−2a−0)2+(3a−3)2⇒(2a+4)2+9(a−1)2=4a2+9(a−1)2⇒4a2+16+16a=4a2⇒a=−1⇒ centre ≡(2,−4)⇒ Radius =40 
⇒AM2=(40)2−(37)2⇒2AM=AB=23
JEE Main 2025 — Mathematics Coordinate Geometry
Let a circle C pass through the points (4,2) and (0,2), and its centre lie on 3x+2y+2=0. Then the length of the chord, of the circle C, whose mid-point is (1,2), is :
Held on 29 Jan 2025 · Verified 6 Jul 2026.
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