
3x−2y+12=04y=3x2∴2(3x+12)=3x2⇒x2−2x−8=0⇒x=−2,4 mOA=−3/2, mOB=3tanθ=(1−292−3−3)=79θ=tan−1(79) (angle will be acute)
JEE Main 2025 — Mathematics Coordinate Geometry
If the line 3x−2y+12=0 intersects the parabola 4y=3x2 at the points A and B, then at the vertex of the parabola, the line segment AB subtends an angle equal to
Held on 23 Jan 2025 · Verified 6 Jul 2026.
tan−1(54)
tan−1(79)
tan−1(911)
2π−tan−1(23)
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