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If the equation of the hyperbola with foci (4,2) and (8,2) is 3 x^2-y^2-α x+β y+γ=0, then α+β+γ is equal to . JEE Main 2025 Mathematics, Hyperbola —…

JEE Main 2025 — Mathematics Coordinate Geometry

2025integereasy

If the equation of the hyperbola with foci (4,2)(4,2)(4,2) and (8,2)(8,2)(8,2) is 3x2−y2−αx+βy+γ=03 x^2-y^2-\alpha x+\beta y+\gamma=03x2−y2−αx+βy+γ=0, then α+β+γ\alpha+\beta+\gammaα+β+γ is equal to _____.

JEE Main 2025 Mathematics, Hyperbola — question figure

Official previous-year question

Held on 3 Apr 2025 · Verified 6 Jul 2026.

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