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If α x+β y=109 is the equation of the chord of the ellipse x^2 9+ y^2 4=1, whose mid point is ( 5 2, 1 2 ), then α+β is equal to :

JEE Main 2025 — Mathematics Coordinate Geometry

2025mcqmedium

If αx+βy=109\alpha x+\beta y=109αx+βy=109 is the equation of the chord of the ellipse x29+y24=1\frac{x^2}{9}+\frac{y^2}{4}=19x2​+4y2​=1, whose mid point is (52,12)\left(\frac{5}{2}, \frac{1}{2}\right)(25​,21​), then α+β\alpha+\betaα+β is equal to :

Official previous-year question

Held on 29 Jan 2025 · Verified 6 Jul 2026.

Options

  1. A

    58

  2. B

    46

  3. C

    37

  4. D

    72

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