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Consider the hyperbola x^2 a^2- y^2 b^2=1 having one of its focus at P(-3,0). If the latus ractum through its other focus subtends a right angle at P…

JEE Main 2025 — Mathematics Coordinate Geometry

2025integermedium

Consider the hyperbola x2a2−y2b2=1\frac{x^2}{a^2}-\frac{y^2}{b^2}=1a2x2​−b2y2​=1 having one of its focus at P(−3,0)\mathrm{P}(-3,0)P(−3,0). If the latus ractum through its other focus subtends a right angle at P and a2b2=α2−β,α,β∈Na^2 b^2=\alpha \sqrt{2}-\beta, \alpha, \beta \in \mathbb{N}a2b2=α2​−β,α,β∈N.

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Held on 7 Apr 2025 · Verified 6 Jul 2026.

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