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The length of the chord of the ellipse x^2 25+ y^2 16=1, whose mid point is (1, 2 5), is equal to:

JEE Main 2024 — Mathematics Coordinate Geometry

2024mcqmedium

The length of the chord of the ellipse x225+y216=1\frac{{x}^{2}}{25}+\frac{{y}^{2}}{16}=125x2​+16y2​=1, whose mid point is (1,25)(1,\frac{2}{5})(1,52​), is equal to:

Official previous-year question

Held on 27 Jan 2024 · Verified 6 Jul 2026.

Options

  1. A

    16915\frac{\sqrt{1691}}{5}51691​​

  2. B

    20095\frac{\sqrt{2009}}{5}52009​​

  3. C

    17415\frac{\sqrt{1741}}{5}51741​​

  4. D

    15415\frac{\sqrt{1541}}{5}51541​​

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