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The distance of the point (2,3) from the line 2x-3y+28=0, measured parallel to the line √3x-y+1=0, is equal to

JEE Main 2024 — Mathematics Coordinate Geometry

2024mcqeasy

The distance of the point (2,3)(2,3)(2,3) from the line 2x−3y+28=02x-3y+28=02x−3y+28=0, measured parallel to the line 3x−y+1=0\sqrt{3}x-y+1=03​x−y+1=0, is equal to

Official previous-year question

Held on 29 Jan 2024 · Verified 6 Jul 2026.

Options

  1. A

    424\sqrt{2}42​

  2. B

    636\sqrt{3}63​

  3. C

    3+423+4\sqrt{2}3+42​

  4. D

    4+634+6\sqrt{3}4+63​

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