Given: Length of latus rectum of ellipse is 14.
⇒a2b2=14...(i)
Also, eccentricity is given as 21
⇒21=1−a2b2
⇒21=1−a2b2
⇒21=1−2a2a14
⇒2−1=−2a14
⇒a=14
⇒a2=14,b2=7
Now, eH=1+a2b2
⇒eH=1+21
⇒eH=23
⇒(eH)2=23
JEE Main 2024 — Mathematics Coordinate Geometry
Let a2x2+b2y2=1,a>b be an ellipse, whose eccentricity is 21 and the length of the latus rectum is 14. Then the square of the eccentricity of a2x2−b2y2=1 is:
Held on 1 Feb 2024 · Verified 6 Jul 2026.
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