P(x,y)&x≥3
Slope of line at P(x,y) will be dxdy=21(x−3y+5) $\begin{aligned}
& \Rightarrow 2 \frac{d y}{(y+5)}=\frac{1}{(x-3)} d x \
& \Rightarrow 2 \ln (y+5)=\ln (x-3)+C
\end{aligned}$
Passes through (4,−2) $\begin{aligned}
& \Rightarrow 2 \ln (3)=\ln (1)+C \
& \Rightarrow C=2 \ln (3) \
& \Rightarrow 2 \ln (y+5)=\ln (x-3)+2 \ln (3) \
& \Rightarrow 2\left(\ln \left(\frac{y+5}{3}\right)\right)=\ln (x-3) \
& \Rightarrow\left(\frac{y+5}{3}\right)^2=(x-3)
\end{aligned}\Rightarrow(y+5)^2=9(x-3)$
Parabola $\begin{gathered}
4 a=9 \
a=\frac{9}{4}
\end{gathered}$

d=(47)2+62d=4625d=42512d=75