∵r=sΔ=4⋅23a3a2=23a=2312=23 
∴A=r2=26 Area =m=A2=24 Perimeter =n=4 A=86∴m+n2=24+384=408
JEE Main 2024 — Mathematics Coordinate Geometry
A circle is inscribed in an equilateral triangle of side of length 12 . If the area and perimeter of any square inscribed in this circle are m and n, respectively, then m+n2 is equal to
Held on 6 Apr 2024 · Verified 6 Jul 2026.
408
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