Skip to main content

Let the eccentricity of an ellipse x^2 a^2+ y^2 b^2=1 is reciprocal to that of the hyperbola 2x^2-2y^2=1. If the ellipse intersects the hyperbola at…

JEE Main 2023 — Mathematics Coordinate Geometry

2023integereasy

Let the eccentricity of an ellipse x2a2+y2b2=1\frac{{x}^{2}}{{a}^{2}}+\frac{{y}^{2}}{{b}^{2}}=1a2x2​+b2y2​=1 is reciprocal to that of the hyperbola 2x2−2y2=12{x}^{2}-2{y}^{2}=12x2−2y2=1. If the ellipse intersects the hyperbola at right angles, then square of length of the latus-rectum of the ellipse is _____.

Official previous-year question

Held on 6 Apr 2023 · Verified 6 Jul 2026.

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

JEE Main Coordinate Geometry in other years

More JEE Main Coordinate Geometry questions

Other Mathematics topics for JEE Main

Keep practicing Coordinate Geometry

Work through every JEE Main Coordinate Geometry PYQ, year by year.

Browse all Mathematics topics