Given,
The eccentricity of an ellipse a2x2+b2y2=1 is reciprocal to that of the hyperbola 2x2−2y2=1,
Now eccentricity of rectangular hyperbola 2x2−2y2=1 is eH=2
So, ee=21
Now, focus of hyperbola =(±1,0)
Now given that both curve intersect orthogonally, so ellipse and hyperbola are confocal
So, for ellipse aee=1⇒a=2
Now length of latusrectum L.R.=a2b2=2a(1−ee2)
=22.21=2