We have been given the length of focal chord PQ=100.

Length of focal chord at (t)=a(t+t1)2=100
Where a=9
t+t1=±310
∴t=3,31,−3,3−1
Since ordinate of P is +ve

∴t=3 or 31
(t=3 as slope of PQ is positive)
∴M(21,9)
Required line:y−9=60−80(x−21)
⇒4x+3y=111
(−3,43) does not lie on line.
Hence this is the correct option.