Given, the area of the triangle with vertices A(1,α),B(α,0) and C(0,α) be 4 sq. units Now applying formula for area we get,
21∣α100αα111∣=±4
⇒α=±8
Now given points will be (8,−8),(−8,8),(64,β)
OR (−8,8),(8,−8),(64,β)
Given above points are collinear, so their slope will be equal, so slope=−8−88+8=−1
⇒64+8β−8=−1
⇒β=−64